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Exercise 2.32

This works because the power set of a set is the union of the subsets not using one element and the subsets using this element.\ Here is the mathematical representation of the idea we used in our procedure: \((\{x_1,x_2,…,x_n\})=(\{x_2,x_3,…,x_n\})\{x_1X:X(\{x_2,x_3,…,x_n\})\}\)